输出成 1,233,232 形式

ljian <[email protected]>
reply-to        [email protected]
to      python-cn`CPyUG`华蟒用户组 <[email protected]>
date    Tue, Jan 13, 2009 at 16:05
subject [CPyUG:76794] python怎么输出1,233,232这种形式？

有现成库么？

locale

国外同志们有遇到同样的问题。看这里：

• http://bytes.com/groups/python/454763-number-format-function

其中有个回帖是这样的。

• This is a little faster:

    def number_format(num, places=0):
    """Format a number according to locality and given places"""
    locale.setlocale(locale.LC_ALL, "")
    return locale.format("%.*f", (places, num), True)

    I tested this ok with my test

再一例

eric <[email protected]>
reply-to        [email protected]
to      python-cn`CPyUG`华蟒用户组 <[email protected]>
date    Tue, Jan 13, 2009 at 16:53
subject [CPyUG:76807] Re: python怎么输出1,233,232这种形式？

http://www.jaharmi.com/2008/05/26/format_numbers_with_the_python_locale_module

>>> import locale
>>> a = {'size': 123456789, 'unit': 'bytes'}
>>> print(locale.format("%(size).2f", a, 1))
123456789.00
>>> locale.setlocale(locale.LC_ALL, '') # Set the locale for your system
'en_US.UTF-8'
>>> print(locale.format("%(size).2f", a, 1))
123,456,789.00

DIY

smallfish <[email protected]>
reply-to        [email protected]
to      [email protected]
date    Tue, Jan 13, 2009 at 16:53
subject [CPyUG:76806] Re: python怎么输出1,233,232这种形式？

我试了一个土方法：

>>> s = "1234567890"
>>> s = s[::-1]
>>> a = [s[i:i+3] for i in range(0,len(s),3)]
>>> print (",".join(a))[::-1]

反馈

创建 by -- ZoomQuiet [2009-01-13 09:10:43]