##language:zh
#pragma section-numbers off
##含有章节索引导航的 ZPyUG 文章通用模板
<<TableOfContents>>
## 默许导航,请保留
<<Include(ZPyUGnav)>>


= 秒杀 list 中的空item  =


##startInc
== filter(lambda) ==
{{{
Heroboy <yangweiqin@gmail.com>
reply-to	python-cn@googlegroups.com
to	python-cn@googlegroups.com
date	Fri, Jan 9, 2009 at 15:30
subject	[CPyUG:76474] Re: 怎么用快速把一个list中的空item去除？
}}}

`aa=filter(lambda x:x=='',aa);`

== 列表推导 ==
{{{
smallfish <smallfish@live.cn>
reply-to	python-cn@googlegroups.com
to	python-cn@googlegroups.com
date	Fri, Jan 9, 2009 at 15:31
subject	[CPyUG:76475] Re: 怎么用快速把一个list中的空item去除？
}}}
	
{{{	
1.
aa = [for i in aa if i != '']
2.
bb = set(aa)
cc = [for i in bb if i != '']
}}}

{{{
khsing <khsing.cn@gmail.com>
reply-to	python-cn@googlegroups.com
to	python-cn@googlegroups.com
date	Fri, Jan 9, 2009 at 18:20
}}}
`[i for i in list if i]`
{{{
LaiYonghao <lanphaday@gmail.com>
reply-to	python-cn@googlegroups.com
to	python-cn@googlegroups.com
date	Fri, Jan 9, 2009 at 18:48
}}}

突然想起，楼主的空行的意思估计是指由空白符组成的行。
那就得用 
`lines = [line for line in f if not line.isspace()]`

== itertools.ifiter() ==
{{{
Heroboy <yangweiqin@gmail.com>
reply-to	python-cn@googlegroups.com
to	python-cn@googlegroups.com
date	Fri, Jan 9, 2009 at 16:45
subject	[CPyUG:76494] Re: 怎么用快速把一个list中的空item去除？
}}}	
{{{	
for i in itertools.ifiter(f,lambda x:x):
    pass
}}}

== filter() ==
{{{
Liu Qishuai <lqs.buaa@gmail.com>
reply-to	python-cn@googlegroups.com
to	python-cn`CPyUG`华蟒用户组 <python-cn@googlegroups.com>
date	Fri, Jan 9, 2009 at 17:06
subject	[CPyUG:76495] Re: 怎么用快速把一个list中的空item去除？
}}}

`a = filter(None, a)`

##endInc

----
'''反馈'''