秒杀 list 中的空item

filter(lambda)

Heroboy <yangweiqin@gmail.com>
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date    Fri, Jan 9, 2009 at 15:30
subject [CPyUG:76474] Re: 怎么用快速把一个list中的空item去除？

aa=filter(lambda x:x=='',aa);

列表推导

smallfish <smallfish@live.cn>
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date    Fri, Jan 9, 2009 at 15:31
subject [CPyUG:76475] Re: 怎么用快速把一个list中的空item去除？

1.
aa = [for i in aa if i != '']
2.
bb = set(aa)
cc = [for i in bb if i != '']

khsing <khsing.cn@gmail.com>
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date    Fri, Jan 9, 2009 at 18:20

[i for i in list if i]

LaiYonghao <lanphaday@gmail.com>
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date    Fri, Jan 9, 2009 at 18:48

突然想起，楼主的空行的意思估计是指由空白符组成的行。 那就得用 lines = [line for line in f if not line.isspace()]

itertools.ifiter()

Heroboy <yangweiqin@gmail.com>
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date    Fri, Jan 9, 2009 at 16:45
subject [CPyUG:76494] Re: 怎么用快速把一个list中的空item去除？

for i in itertools.ifiter(f,lambda x:x):
    pass

filter()

Liu Qishuai <lqs.buaa@gmail.com>
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date    Fri, Jan 9, 2009 at 17:06
subject [CPyUG:76495] Re: 怎么用快速把一个list中的空item去除？

a = filter(None, a)

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